Halloween Weekend Post
POWER OUTAGE UPDATE!!
Ask questions now, or
Tues Wednesday Thursday will be a very scary day!
I will be available
Mon Tuesday Wednesday after school for extra help... I may also be available Weds morning at 7am... but not sure about that right now.
I'm thinkin' that if I don't get many questions over the weekend itz becuz u guys "getz it" so I think I'll probly redo the test and put in some harder questions, cuz you wants to be challenged more... yeah, that's what I'm thinkin'... what are you thinkin'??
ReplyDeletecould you post an example problem with 2 or3 variables ( ex ab over 3c blah blah )im still getting a little stumped on them mostly technicalities but just need some practice
ReplyDeleteI'm having trouble on #24, pg 154.
ReplyDeleteI added 2 to both sides, multilied by the reciprocal, and came out w/ x+6=x
no school tomorrow :( does tht mean tht the study session is on tuesday afternoon or should we come in early?
ReplyDeleteIF there is no school tomorrow, I will be available after school on Tues... I have not been notified that there is no school.
ReplyDeletefor me pg 154 #24 is
ReplyDelete(2/3)x + 4 = (3/5)x - 2
I don't see a 'w'... are we looking at the same problem... you may have an older version of the text book... what is the original problem?
my dad got a call that said school was closed so i dont know but anyways can you post an example please? (previous blog post)
ReplyDeleteIt's the same problem. I just abbreviated with as w/ the "w" isn't part of the problem. Sorry.
ReplyDeleteOh, ok, I'm not that smart!!!
ReplyDeletepg 154 #24 is: (2/3)x + 4 = (3/5)x - 2
There are several different first steps to move forward and solve this problem.
One first step would be to use a common denominator...
(2/3)x + 4 = (3/5)x - 2
(10/15)x + 4 = (9/15)x - 2 "simplify w/commn denom"
(1/15)x + 4 = -2 "sub POE"
(1/15)x = -6 "sub POE again"
x = -90 "mult POE"
... don't forget to √ your answer!!
Here is another really FUN way... multiply through by the LCD (Least Common Denominator) to get rid of those fractions... JUST MAKE SURE that you multiply the full side (use parens PLEASE!!)
(2/3)x + 4 = (3/5)x - 2
15[(2/3)x + 4] = [(3/5)x - 2](15) "mult POE"
10x + 60 = 9x - 30
x + 60 = -30 "sub POE"
x = -90 "sub POE again"
Two different approaches yield the same answer... YAY for algebra!!
It is VERY IMPORTANT to notice up above that SIMPLIFYING using a common denominator DID NOT CHANGE THE VALUE OF ANYTHING... a beginning algebra student might erroneously think that "different" things were done to both sides... BUT (with one 't')... in fact the (2/3)x was multiplied by (5/5) (that's a BIG PHAT ONE) and the (3/5)x was multiplied by (3/3) (also a BIG PHAT ONE). You can multiply by ONE all you want, on one or both sides of an equation AND you are not changing the value of ANYTHING!
ReplyDeleteThese comments are coming to you from the Kinnelon Public Library... I still don't have internet access at my house, so I may not be communicating with you tonight. If we have school tomorrow (Tuesday) I plan to be around after school for extra help, but I can't guarantee anything since they might send everyone home on the 2:30 buses. Get your questions in now and help each other.
ReplyDeleteCan you solve #31 on pg 154? Something like that would look GREAT on the test!
#31 Solve for x: [(x+r)/t] + 1 = 0
What FUN!!
No school tomorrow either! And wednesday study session isn't possible select and lantern can i come in early Wednesday?
ReplyDeleteI'll keep you posted... not sure at this point if I can be there on Weds morning... ask questions on the blog!!!!!!!!!!!!!!!! Did my answer above help??
ReplyDeletefor number 31 i got x-r= -t but looking in the back of the book it says tht its x=-t-r so thts confusing for the first step i added 1 to both sides getting x+r over t = -1 my next step was creating a proportion so it was x+r/t = -1/-1 i multiplied each side then and for t i got -t and i distributed the -1 creating -x-r=-t can you point out my mistake? Thnks again for taking the time to help us out! We need it :)
ReplyDeleteOK #31 Solve for x: [(x+r)/t] + 1 = 0
ReplyDelete(BRACKETS AND PARENTHESES ADDED TO PROBLEM TO SHOW THE IMPACT OF THE FRACTION BAR AS A GROUPING SYMBOL)
[(x+r)/t] + 1 = 0
[(x+r)/t] = -1 (sub POE.. sub 1 fbs*))
(x+r) = -t (mult POE.. mult bs** by t)
x = -t - r (sub POE.. sub r fbs)
Abbrevs:
fbs* from both sides
bs** both sides
Ca-peesh??
btw, you saids you ADDED 1 tbs, but you actually subtracted, yes?
Your error: When you created your proportion, you converted -1 into -1/-1... oops... -1 over -1 is actually POSITIVE 1... and that was your error. Otherwise, creating a proportion was a perfectly good strategy.
I did the problem above without using a proportion, just to show another way.
Good news/bad news... there is always more than one way to solve equations... the more complex the equations get, the more ways you will have to choose from. You'll develop some favorite techniques, but it's good to have an appreciation for all methods.
Mr. C.
Yea I did subtract and thanks I get it there's just so many technicalities! It messes me up sometimes :)
ReplyDeleteCan you explain this problem?
ReplyDelete2r-(5-r)=13+2r
Ok... 2r-(5-r)=13+2r
ReplyDeleteREMEMBER, you are subtracting everything inside the schmegeggy, so you are subtracting 5 and you are subtracting -r (we called this technique "distributing the negative", yes?)
So, after we distribute the negative, we have:
2r-5+r=13+2r (simplify distribute the negative)
3r-5=2r+13 (simplify CombneLkeTrms)
r-5=13 (sub POE)
r=18 (add POE)
I'll let you check the answer!
Ca-peesh?
Mr. C.
Can you explain problem 21 in the chapter review
ReplyDeletewait since we just came back to school is the test tomorrow
ReplyDeleteYou've had all these extra days to study!!! Yes, the test is tomorrow!!
ReplyDeleteCan someone else explain #21, I have to hit the road... Mr. C.
2+y
ReplyDelete____ = -1
3
???????????
For number 25 on pg 154 I'm a little confused about how I go about answering it. its 6-.25f=f-3 so for my first step would if I add f to .25f would that be 2f(.25)HELP!! Btw is there going to be a study session tomorrow??
ReplyDeleteSORRY! But I have another question. For number #29 I'm confused about the equation I would write out I tried creating a proportion 65/1 times 130/1 but then I got stumped a little help please?
ReplyDeletewheres the online textbook anyone? gotta power problem and i cant go home, at a friends, so can anyone tell me where the online textbook is, or what I should do
ReplyDeletenevermind, found the textbook but whats the web code? Mr. C.?
ReplyDeleteFor number 63 on Page 156 how would I divide hours and minutes for percent increase?
ReplyDeleteNever mind I got it :)
ReplyDeletenobody? not even the brilliant candace?
ReplyDeleteim doing practice problems on pearson.com on each unit but... its not the textbook
what about this problem a model deck is 9 inches by 16 inches. The scale is 1/2 inch=1ft. I know the answer is 18 ft by 32 ft, but why?
ReplyDeletehey guys can some body show me how the textbook answer for #33 on the old home work is right.cause i cant figure it out
ReplyDeleteWhat page?
ReplyDeleteChap 2 Review #21
ReplyDelete2x/7 + 4/5 = 5
Lots of ways to start this one...
How about
2x/7 = 4 1/5 (sub POE)
2x/7 = 21/5 (convert to improper)
WOWZERS!! We gotsk ourselves a proportion!
5(2x) = 7(21) (cross-product property)
10x = 147 (simplify)
x = 14.7 (div POE)
too easy, eh??
For pg 154#29
ReplyDeletetrain 65mph for h hours
plane at 130mph for (h-3) hours
d=rt, so the train goes a distance of 65h and the plane goes a distance of 130(h-3)... we just wanna know when they are the same, so...
65h = 130(h-3)
65h = 130h - 390 (Simplify Distribute)
-65h = -390 (Add POE)
h = 3 (div POE)
ca-peeesh??
what exactly is percent error? can i see a problem
ReplyDeleteFor the model, of 1/2 inch = 1ft then, well 12 in div by 1/2" = 24, so for every inch in the model there is 2ft on the actual deck, yes? Does that answer the question?
ReplyDeleteI'll be in by 7:15am tomorrow morning... but I'm going to bed... see ya!
ReplyDelete#33 on the 152-157 review.
ReplyDeleteYea i got it 29 thnks:)
ReplyDelete