This is a HUGE assignment, since most of you did not do the Unit 1-9 Assignment over the weekend. You will have a brief quiz next Monday, June 4th on Pythagorean Theorem and Radical Expressions (10-1 and 10-2) and the FINAL EXAM will be on Friday, June 8th. I will provide one more assignment for final exam prep... PREPARE AS YOU SEE FIT... I'm here to assist as best I can.
If you can't do all of the Odds, maybe do every other odd... you decide what works for you.
hw #10-2
pg 623
#1-21 Odd, 22
Treat the questions as open-ended as best you can. Ignore the "directions" which ask you to record your answers "in a grid."
Do the work on separate notebook or graph paper and hand-in as a stand-alone assignment on Tuesday.
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Mr.C I don't understand how to solve #21 on pg 617 on hw #10-1. I tried mapping the joggers path into a triagnle and plugging in the numbers for the Pythagorean Theorem, but it didn't come out to the right answer. Could you help???
ReplyDelete#21) A jogger boes half a mile north and then turns west. If the jogger finishes 1.3 miles from the starting point, how far west did the jogger go?
DeleteOne fact that you must read into this problem is that the distance of 1.3 miles is measured diagonally i.e. it's the hypotenuse, even though the jogger ran only along the "legs" of the right triangle formed by his/her run.
We know the Pythagorean Theorem, where a & b are the legs and c is the hypotenuse of a right triangle:
a^2 + b^2 = c^2
It also follows from our knowledge of manipulating equations (remember literal equations?) that
c^2 - a^2 = b^2... which is a useful formula when the length of a leg is missing, as in this problem.
SO...
(1.3)^2 - (.5)^2 = b^2
Got a calculator?
Capeesh?
so I have a question on #5 on the Cumulative review. i tried all four answers, but it seems like none of them work. Also, i think i need help getting started on # 14. and do you mean the Cumulative review is due monday?
ReplyDeleteFor #5, the arithmetic sequence is 3,8,13,18,23
Deletethe answer is B, which is A(n) = 3 + (n-1)5
A(1) = 3 + (1-1)5 = 3
A(2) = 3 + (2-1)5 = 8
A(3) = 3 + (3-1)5 = 13
... and so on
haha... "TUESDAY" refers to last Tuesday May 29th... I extended the date until tomorrow... the assignment is for your benefit... the more you do and ask questions, the better you will do on the final...
ohhh ok i understand now. what about for #14?im so confused on how to do that, do i convert the feet into inches?
DeleteMaybe we just need more sleep... are you really asking me how many inches are in a foot?
DeleteIt is always helpful to restate the problem in terms of a single unit of measure (UOM) when possible.
In this case a 6' by 8' room is being tiles with 4" square tiles. So couldn't we say that the room is 72" by 96" (I used the "trick" of converting inches to feet by multiplying the number of feet by 12).
If you are still stuck, a picture will likely "un-stick" you.
P.S. ALWAYS DRAW A PICTURE!!
haha i did that and i wanted to make you do convert the feet into inces
DeleteI need help on number 5 on page 623. i tried finding the square roots for the problem but then i checked the answers in the back of the book and it says thats wrong.
ReplyDeleteThe technique for simplifying an expression such as this is called "rationalizing the denominator" and is described on page 622.
DeleteYou are asked to simplify: √5 / √3
Well, it looks pretty simple already, BUT (with one 't') it is violating the "rule" that no radicals are allowed in the denominator of a fraction.
SO, how can we change the denominator into an integer? Multiply it by √3 and it will become 3. BUT (again) we can't just impact the denominator, that would change the value of the expression. The only number we can multiply the expression by is a BIG PHAT ONE... in this case, we will use √3/√3
SO, that will yield √15/3, which IS the simplified expression.
Capeesh?
This is one of those rationalizing denominators problems, so you wouldn't have to try and square root right away. For this prob you would multiply by √3/√3 (big fat 1). When you multiply you should come out w/ √15/√9. Lastly you have to simplify the 9 because that is the only perfect square. You end up with √15/3.
DeleteMr. C I think we posted at the same time or your post just popped up when I published haha, sorry.
Deletethank you i get it! but how do you simplify problems that have numbers outside to the left of the radical sign?
DeleteBy the way, I am postponing tomorrow's pd5 algebra quiz until Weds (you're welcome)... I will give you a short pre-quiz so you can do a "self-check" in preparation for the quiz on Weds. DON'T FORGET! The final is on Friday (I thought you might have forgotten!).
ReplyDeleteMost of tomorrow's (and Weds) class will be a review of the final review packet and the Unit 9 cumulative review. It would be helpful for me to know any questions you have IN ADVANCE so that I can be better prepared to demonstrate for you... so send a blog comment tonight, why dont'cha?
Mr. C.
no quiz tomorrow = going to sleep
ReplyDelete