This Blog exists for the collective benefit of all algebra students. While the posts are specific to Mr. Chamberlain's class, any and all "algebra-ticians" are welcome. The more specific your question (including your own attempts to answer it) the better.
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Tuesday, February 21, 2012
hw #6-5 & 6-6 and ProbSet 6F
Remember, I would like you to do a "reasonable" subset of the 6-5 and 6-6 homework... Thursday is our review session for Monday's test... the more ready you are for Thurs, the better shape you'll be in for Monday.
for number 4, a on set 6f what was the third equation. i got x< or = to 250 and Y< or = to 200 but the third has cofused me.does it have something to do with the home school assosiation
I'm having trouble on #1. I'm not compleatly sure what the inequalities that we had to make were. and on #3 im not compleatly sure how to graph y>-4. Is the -4 on the y axis or what?
Take a breath... when you graph a single linear inequality you will see TWO THINGS in the coordinate plane... a LINE and a SHADED REGION. To graph the line, change it to an equation. Where is the line y=-4? It's a horizontal line with a y-intercept of -4, yes?
Hmmm, where are the y-values GREATER THAN -4? Above the line, right? So shade above the line.
Don't forget... is the line dashed or solid? For > or <, the line is dashed (i.e. NOT included in the solution region). For >= or <=, the line is solid (i.e. included in the solution region).
for number 4, a on set 6f what was the third equation. i got x< or = to 250 and Y< or = to 200 but the third has cofused me.does it have something to do with the home school assosiation
ReplyDeleteYup... #4 is a doozie (google it!)...
ReplyDeleteif we only made money from students, one line would be
y = 3x
... since we know we made at least $100 due to the HSA donation, the new MIMIMUM is
y >= 3x + 100
... since we could make UP TO $200 more on the bake sale, the new MAXIMUM is
y <= 3x + 100 + 200 which simplifies to:
y <= 3x + 300
Ca-peesh??
That is a very tough one... if that is your only problem, you are doing just fine... thanks for asking!!
I'm having trouble on #1. I'm not compleatly sure what the inequalities that we had to make were. and on #3 im not compleatly sure how to graph y>-4. Is the -4 on the y axis or what?
ReplyDeleteTake a breath... when you graph a single linear inequality you will see TWO THINGS in the coordinate plane... a LINE and a SHADED REGION. To graph the line, change it to an equation. Where is the line y=-4? It's a horizontal line with a y-intercept of -4, yes?
ReplyDeleteHmmm, where are the y-values GREATER THAN -4? Above the line, right? So shade above the line.
Don't forget... is the line dashed or solid? For > or <, the line is dashed (i.e. NOT included in the solution region). For >= or <=, the line is solid (i.e. included in the solution region).
Capeesh?
For #1, you should recognize this situation from a prior problem set:
ReplyDeleteThe inequalities are:
3x + 5y > 1875
this means that $3 for each student plus $5 for each adult will be more than $1,875...
and
x+y <= 900 means that no more than 900 people can attend the game.
Capeesh?
I'm having trouble with number 27 on page 403
ReplyDelete-katie
I was going over the chapter review and i had one question on question number 18 on page 409, I would like some assistance please
ReplyDeleteI'll move your question to the current post... let me know how you tried to get started...
ReplyDelete